Cod sursa(job #548586)

Utilizator BitOneSAlexandru BitOne Data 7 martie 2011 16:39:21
Problema Arbore partial de cost minim Scor 80
Compilator cpp Status done
Runda Arhiva educationala Marime 1.62 kb
#include <vector>
#include <fstream>
#include <cstdlib>
#define N_MAX 200011
#define oo 1<<28
#define pr pair< int, int >
#define mkpr make_pair< int, int >

using namespace std;
int lHeap;
int apm[N_MAX];
int d[N_MAX], P[N_MAX], H[N_MAX];
vector< pr > G[N_MAX];
vector< pr >::const_iterator it, iend;
void DownHeap( int k )
{
	for( int son=2*k; son <= lHeap; k=son, son=k*2 )
	{
		if( son < lHeap && d[H[son+1]] < d[H[son]] )
			++son;
		if( d[H[k]] <= d[H[son]] )
			return;
		swap( H[k], H[son] );
		P[H[k]]=k;
		P[H[son]]=son;
	}
}
void UpHeap( int k )
{
	for( int key=d[H[k]], f=k/2; k > 1 && key < d[H[f]]; k=f, f/=2 )
	{
		swap( H[k], H[f] );
		P[H[f]]=f;
		P[H[k]]=k;
	}
}
inline void push( int k )
{
	H[++lHeap]=k;
	P[k]=lHeap;
	UpHeap( lHeap );
}
inline int pop()
{
	int r=H[1];
	P[H[1]]=-1;
	P[H[lHeap]]=1;
	H[1]=H[lHeap];
	--lHeap;
	DownHeap( 1 );
	return r;
}
int main( void )
{
	int N, M, x, y, c, s=0;
	ifstream in( "apm.in" );
	for( in>>N>>M; M; --M )
	{
		in>>x>>y>>c;
		G[x].push_back( mkpr( y, c ) );
		G[y].push_back( mkpr( x, c ) );
	}
	for( push(1); lHeap; )
	{
		x=pop();
		s+=d[x];
		for( it=G[x].begin(), iend=G[x].end(); it < iend; ++it )
			if( 0 == P[it->first] )
			{
				apm[it->first]=x;
				d[it->first]=it->second;
				push( it->first );
			}
			else if( P[it->first] > 0 && d[it->first] > it->second )
				 {
					 d[it->first]=it->second;
					 apm[it->first]=x;
					 UpHeap( P[it->first] );
				 }
	}
	ofstream out( "apm.out" );
	out<<s<<'\n'<<(N-1)<<'\n';
	for( y=2; y <= N; ++y )
		out<<y<<' '<<apm[y]<<'\n';
	return EXIT_SUCCESS;
}