Cod sursa(job #3342953)

Utilizator mariaprvPirvan Maria mariaprv Data 26 februarie 2026 10:36:12
Problema Arbore partial de cost minim Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.06 kb
#include <fstream>
#include <queue>
#define NMAX 200005
#define MMAX 400005
using namespace std;

ifstream fin("apm.in");
ofstream fout("apm.out");

struct muchie{
    int x, y, c;
    friend bool operator < (muchie a, muchie b);
};

muchie apm[NMAX];

int n, m;
int tata[NMAX];
int h[NMAX]; /// h[x] = inaltimea arborelui cu radacina x
int costmin;

bool operator < (muchie a, muchie b){
    return a.c>b.c;
}

int Find(int x);
void Union(int x, int y);
void citire();
void kruskal();
void afisare();

priority_queue <muchie> H;

int main()
{
    citire();
    kruskal();
    afisare();
    return 0;
}

void citire(){
    int i, x, y, c;
    muchie aux;
    fin>>n>>m;
    for (i=0; i<m; i++){
        fin>>aux.x>>aux.y>>aux.c;
        H.push(aux);
    }
}

void kruskal(){
    muchie aux;
    int rx, ry, nrsel;
    nrsel=0;
    while (nrsel<n-1){
        aux=H.top(); H.pop();
        rx=Find(aux.x); ry=Find(aux.y);
        if (rx!=ry){
            costmin+=aux.c;
            apm[++nrsel]=aux;
            Union(rx, ry);
        }
    }
}

int Find(int x){
    int y, rx;
    /// determin radacina arborelui
    rx=x;
    while (tata[rx]!=0){
        rx=tata[rx];
    }
    /// rx este radacina arborelui
    /// compresez drumul de la x la rx
    /// fiecare nod de pe acest drum devine fiu al lui x

    while (tata[x]!=0 && rx!=tata[x]){
        y=tata[x];
        tata[x]=rx;
        x=y;
    }
    return rx;
}

void Union(int x, int y){
    int rx, ry;
    /// reuneste arborele in care se afla x cu arborele in care se afla y
    rx=Find(x); ry=Find(y);
    if (h[rx]<h[ry]){
        /// rx devine fiul lui ry
        tata[rx]=ry;
    }
    else{
        if (h[ry]<h[rx]){
            /// ry devine fiul lui rx
            tata[ry]=rx;
        }
        else{ /// egalitate
            tata[ry]=rx;
            h[rx]++;
        }
    }
}

void afisare(){
    int i;
    fout<<costmin<<'\n'<<n-1<<'\n';
    for (i=1; i<n; i++){
        fout<<apm[i].x<<" "<<apm[i].y<<'\n';
    }
}