Cod sursa(job #3342951)

Utilizator Teodora_ProdanTeodora Prodan Teodora_Prodan Data 26 februarie 2026 10:36:05
Problema Arbore partial de cost minim Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 1.98 kb
#include <fstream>
#include <queue>
#define NMAX 200002
#define LMAX 400002
using namespace std;
ifstream fin ("apm.in");
ofstream fout ("apm.out");
int n, m;
int tata[NMAX];
struct muchie {int x, y, c;
                friend bool operator < (muchie a, muchie b); };
int h[NMAX];//h arbore cu rad x
int Find(int x);
void Union(int x, int y);
void citire();
void kruskal();
void afisare();
muchie apm[NMAX];
int costmin;
bool operator < (muchie a, muchie b)
{
    return a.c>b.c;

}
priority_queue<muchie> H;
int main()
{
    citire();
    kruskal();
    afisare();
    return 0;
}
int Find(int x)
{
    int y, rx;
    //det rad arborelui
    rx=x;
    while(tata[rx]!=0)
        rx=tata[rx];
    //rx este rad
    //compresez drumul de la x la rx; fiecare nod de pe acest drum devine fiu al lui rx
    while (tata[x] && tata[x]!=rx)
    {
        y=tata[x];
        tata[x]=rx;
        x=y;
    }
    return rx;
}
void Union(int x, int y)
{
    int rx, ry;
    //reuneste arborele in care se afla x cu arborele in care se afla y
    rx=Find(x);
    ry=Find(y);
    if(h[rx]<h[ry])
        //rx devine fiul lui ry
        tata[rx]=ry;
    else
        if(h[ry]<h[rx]) //ry devine fiul lui rx
            tata[ry]=rx;
        else
        {
            //egalitate
            tata[ry]=rx;
            h[rx]++;
        }
}
void citire()
{
    int i, x, y, c;
    muchie aux;
    fin>>n>>m;
    for(i=0;i<m;i++)
    {
        fin>>aux.x>>aux.y>>aux.c;
        H.push(aux);

    }
}
void kruskal()
{
    muchie aux;
    int nrsel=0;
    int rx, ry;
    while (nrsel<n-1)
    {
        aux=H.top();
        H.pop();
        rx=Find(aux.x);
        ry=Find(aux.y);
        if(rx!=ry)
        {
            costmin+=aux.c;
            apm[++nrsel]=aux;
            Union(rx, ry);
        }
    }
}
void afisare()
{
    int i;
    fout<<costmin<<'\n'<<n-1<<'\n';
    for(i=1;i<n;i++)
        fout<<apm[i].x<<' '<<apm[i].y<<'\n';
}