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#include "bits/stdc++.h"
#include <type_traits>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")
// ============ Macros starts here ============
int recur_depth = 0;
#ifdef DEBUG
#define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\t')<<"\e[91m"<<__func__<<":"<<__LINE__<<"\t"<<#x<<" = "<<x_<<"\e[39m"<<endl;}
#else
#define dbg(x)
#endif // DEBUG
template<typename Ostream, typename Cont>
typename enable_if<is_same<Ostream, ostream>::value, Ostream&>::type operator<<(Ostream& os, const Cont& v) {
os << "[";
for (auto& x : v) { os << x << ", "; }
return os << "]";
}
template<typename Ostream, typename ...Ts>
Ostream& operator<<(Ostream& os, const pair<Ts...>& p) {
return os << "{" << p.first << ", " << p.second << "}";
}
#define readFast \
ios_base::sync_with_stdio(false); \
cin.tie(0); \
cout.tie(0);
#ifdef LOCAL
#define read() ifstream fin("date.in.txt")
#else
#define read() readFast
#endif // LOCAL
// ============ Macros ends here ============
#define fin cin
#define ll long long
#define sz(x) (int)(x).size()
#define all(v) v.begin(), v.end()
#define output(x) (((int)(x) && cout << "YES\n") || cout << "NO\n")
#define LSB(x) (x & (-x))
#define test cout << "WORKS\n";
const int N = 1e5 + 15;
const int MOD = 1e9 + 7; // 998244353
const int INF = 1e9;
int t, n, m;
// vector<int> graf[N];
vector<pair<int, int>> graf[N];
// multiset<pair<int, int>> used;
vector<int> ans;
vector<int> dg;
bool used[N * 5];
int main() {
read();
ifstream fin("ciclueuler.in");
ofstream cout("ciclueuler.out");
fin >> n >> m;
dg.resize(n + 1);
for (int i = 0; i < m; ++i) {
int a, b;
fin >> a >> b;
graf[a].push_back({ b, i });
graf[b].push_back({ a, i });
++dg[a];
++dg[b];
}
for (int i = 1; i <= n; ++i) {
if (dg[i] % 2 == 1) {
cout << -1 << '\n';
return 0;
}
}
stack<int> stk;
stk.push(1);
while (!stk.empty()) {
int node = stk.top();
while (!graf[node].empty() && used[graf[node].back().second]) {
graf[node].pop_back();
}
if (graf[node].empty()) {
stk.pop();
ans.push_back(node);
continue;
}
int to = graf[node].back().first;
int i = graf[node].back().second;
graf[node].pop_back();
used[i] = true;
stk.push(to);
}
ans.pop_back();
for (int x : ans) {
cout << x << " ";
}
return 0;
} /*stuff you should look for !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
* test the solution with the given example
* int overflow, array bounds, matrix bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
~Benq~*/