Cod sursa(job #1939471)

Utilizator BogdanisarBurcea Bogdan Madalin Bogdanisar Data 25 martie 2017 19:17:17
Problema Cele mai apropiate puncte din plan Scor 100
Compilator cpp Status done
Runda Arhiva educationala Marime 2.39 kb
#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
#include <math.h>
#include <iomanip>

using namespace std;
ifstream in("cmap.in");
ofstream out("cmap.out");

const int NMax = 1e5 + 5;
typedef long long ll;
const ll inf = 1e18;

int N;

struct elem {
    int x,y;
}v[NMax],aux[NMax];

bool operator <(elem a,elem b) {
    return a.y < b.y;
}

bool cmp1(elem,elem);
ll dist(elem,elem);
ll solve(int,int);
// dist(A,B) return-eaza patratul distantei intre doua puncte A si B
// solve(i,j) rezolva problema pentru intervalul de indecsi (i,j)
//            din vectorul de input (sortat dupa abscisa)

int main()
{
    in>>N;
    for (int i=1;i<=N;++i) {
        in>>v[i].x>>v[i].y;
    }
    sort(v+1,v+N+1,cmp1);

    double mn = sqrt(solve(1,N));
    out<<fixed<<setprecision(6)<<mn<<'\n';

    return 0;
}

ll solve(int st,int dr) {
    if (dr-st+1 == 1) {
        return inf;
    }
    if (dr-st+1 == 2) {
        if (!(v[st] < v[dr])) {
            swap(v[st],v[dr]);
        }

        return dist(v[st],v[dr]);
    }

    int mij = (st+dr)>>1;
    int abscisa = v[mij].x;
    ll mn = min(solve(st,mij),solve(mij+1,dr));

    // se interclaseaza intervalele determinate de  perechile de indecsi (st,mij), (mij+1,dr)
    // pentru a obtine vectorul de puncte sortat dupa ordonata
    int nrAux = 0;
    int i = st,j = mij + 1;
    while (i <= mij && j <= dr) {
        if (v[i] < v[j]) {
            aux[++nrAux] = v[i++];
        }
        else {
            aux[++nrAux] = v[j++];
        }
    }
    while (i <= mij) {
        aux[++nrAux] = v[i++];
    }
    while (j <= dr) {
        aux[++nrAux] = v[j++];
    }

    for (i=1;i<=nrAux;++i) {
        v[st+i-1] = aux[i];
    }

    // se considera doar punctele aflate la distanta cel mult mn
    // de dreapta verticala ce desparte cele doua multimi de puncte
    nrAux = 0;
    for (i=st;i<=dr;++i) {
        if (abs(v[i].x-abscisa) <= mn) {
            aux[++nrAux] = v[i];
        }
    }

    for (i=1;i<=nrAux;++i) {
        for (j=i+1;j <= nrAux && j-i+1 <= 8;++j) {
            ll d = dist(aux[i],aux[j]);
            mn = min(mn,d);
        }
    }
    return mn;
}

bool cmp1(elem a,elem b) {
    return a.x < b.x;
}

ll dist(elem a,elem b) {
    ll val = 1LL * (a.x - b.x) * (a.x - b.x) + 1LL * (a.y - b.y) * (a.y - b.y);
    return val;
}