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#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
#include <math.h>
#include <iomanip>
using namespace std;
ifstream in("cmap.in");
ofstream out("cmap.out");
const int NMax = 1e5 + 5;
typedef long long ll;
const ll inf = 1e18;
int N;
struct elem {
int x,y;
}v[NMax],aux[NMax];
bool operator <(elem a,elem b) {
/*
if (a.y == b.y) {
return a.x < b.x;
}
//*/
return a.y < b.y;
}
bool cmp1(elem,elem);
double dist(elem,elem);
double solve(int,int);
int main()
{
in>>N;
for (int i=1;i<=N;++i) {
in>>v[i].x>>v[i].y;
}
//cout<<dist(v[2],v[1])<<'\n';
sort(v+1,v+N+1,cmp1);
//cout<<solve(1,2)<<'\n';
double mn = solve(1,N);
out<<fixed<<setprecision(6)<<mn<<'\n';
return 0;
}
double solve(int st,int dr) {
if (dr-st+1 == 1) {
return inf;
}
if (dr-st+1 == 2) {
if (!(v[st] < v[dr])) {
swap(v[st],v[dr]);
}
return dist(v[st],v[dr]);
}
int debug = 0;
//*
if (debug) {
cout<<st<<' '<<dr<<'\n';
for (int i=st;i<=dr;++i) {
cout<<v[i].x<<' '<<v[i].y<<'\n';
}
cout<<'\n';
}
//*/
int mij = (st+dr)>>1;
int abscisa = v[mij].x;
double mn = min(solve(st,mij),solve(mij+1,dr));
//*
if (debug) {
cout<<mn<<'\n';
for (int i=st;i<=dr;++i) {
cout<<v[i].x<<' '<<v[i].y<<'\n';
}
cout<<'\n';
}
//*/
int nrAux = 0;
int i = st,j = mij + 1;
while (i <= mij && j <= dr) {
if (v[i] < v[j]) {
aux[++nrAux] = v[i++];
}
else {
aux[++nrAux] = v[j++];
}
}
while (i <= mij) {
aux[++nrAux] = v[i++];
}
while (j <= dr) {
aux[++nrAux] = v[j++];
}
for (i=1;i<=nrAux;++i) {
v[st+i-1] = aux[i];
if (debug)
cout<<aux[i].x<<' '<<aux[i].y<<'\n';
}
if (debug)
cout<<"\n";
nrAux = 0;
for (i=st;i<=dr;++i) {
if (abs(v[i].x-abscisa) <= mn) {
aux[++nrAux] = v[i];
}
}
for (i=1;i<=nrAux;++i) {
if (debug)
cout<<aux[i].x<<' '<<aux[i].y<<'\n';
for (j=i+1;j <= nrAux && j-i+1 <= 8;++j) {
double d = dist(aux[i],aux[j]);
if (debug) {
cout<<i<<' '<<j<<' '<<d<<'\n';
}
mn = min(mn,d);
}
}
if (debug)
cout<<"\n\n";
return mn;
}
bool cmp1(elem a,elem b) {
/*
if (a.x == b.x) {
return a.y < b.y;
}
//*/
return a.x < b.x;
}
double dist(elem a,elem b) {
double val = sqrt(1LL * (a.x - b.x) * (a.x - b.x) + 1LL * (a.y - b.y) * (a.y - b.y));
return val;
}