Compilare: user.cpp: In function ‘int main()’: user.cpp:27:17: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (op1[tc[i]][1] == td[i]) ^ user.cpp:31:19: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((op1[tc[i]][1] == 0)&&(op1[tc[i]][0] == 0)&& (op2[td[i]][1] == 0) && (op2[td[i]][0] == 0)) ^ user.cpp:31:41: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((op1[tc[i]][1] == 0)&&(op1[tc[i]][0] == 0)&& (op2[td[i]][1] == 0) && (op2[td[i]][0] == 0)) ^ user.cpp:31:64: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((op1[tc[i]][1] == 0)&&(op1[tc[i]][0] == 0)&& (op2[td[i]][1] == 0) && (op2[td[i]][0] == 0)) ^ user.cpp:31:88: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((op1[tc[i]][1] == 0)&&(op1[tc[i]][0] == 0)&& (op2[td[i]][1] == 0) && (op2[td[i]][0] == 0)) ^ user.cpp:33:15: warning: array subscript has type ‘char’ [-Wchar-subscripts] op1[tc[i]][0] = tc[i]; ^ user.cpp:34:15: warning: array subscript has type ‘char’ [-Wchar-subscripts] op1[tc[i]][1] = td[i]; ^ user.cpp:35:15: warning: array subscript has type ‘char’ [-Wchar-subscripts] op2[td[i]][0] = td[i]; ^ user.cpp:36:15: warning: array subscript has type ‘char’ [-Wchar-subscripts] op2[td[i]][1] = tc[i]; ^