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// FMI - Grupa 135 - Semigrupa 2 - Hareza Andrei
// Include
#include <fstream>
#include <queue>
using namespace std;
// Definitii
#define ll long long
// Constante
const int sz = 1000001;
struct treeNode
{
ll value;
int leftSon, rightSon;
treeNode()
{
value = 0;
leftSon = rightSon = 0;
}
};
struct symbol
{
ll times;
int posInTree;
symbol()
{
times = 0;
posInTree = 0;
}
symbol(int newTimes, int newPosInTree)
{
times = newTimes;
posInTree = newPosInTree;
}
bool operator< (symbol x) const
{
return times < x.times;
}
};
// Functii
void dfs(int node, ll currentCode=0, int codeLen=0);
// Variabile
ifstream in("huffman.in");
ofstream out("huffman.out");
int num;
treeNode tree[sz*2];
queue<symbol> firstQueue;
queue<symbol> secondQueue;
ll sum;
// Main
int main()
{
in >> num;
for(int i=1 ; i<=num ; ++i)
{
in >> tree[i].value;
firstQueue.push(symbol(tree[i].value, i));
}
int current = num;
while(firstQueue.size() + secondQueue.size() > 1)
{
symbol son1, son2;
if(firstQueue.empty())
{
son1 = secondQueue.front();
secondQueue.pop();
}
else if(secondQueue.empty())
{
son1 = firstQueue.front();
firstQueue.pop();
}
else
{
if(firstQueue.front().times < secondQueue.front().times)
{
son1 = firstQueue.front();
firstQueue.pop();
}
else
{
son1 = secondQueue.front();
secondQueue.pop();
}
}
if(firstQueue.empty())
{
son2 = secondQueue.front();
secondQueue.pop();
}
else if(secondQueue.empty())
{
son2 = firstQueue.front();
firstQueue.pop();
}
else
{
if(firstQueue.front() < secondQueue.front())
{
son2 = firstQueue.front();
firstQueue.pop();
}
else
{
son2 = secondQueue.front();
secondQueue.pop();
}
}
tree[++current].value = son1.times + son2.times;
tree[current].leftSon = son1.posInTree;
tree[current].rightSon = son2.posInTree;
secondQueue.push(symbol(tree[current].value, current));
}
dfs(current);
out << sum << '\n';
for(int i=1 ; i<=num ; ++i)
out << tree[i].leftSon << ' ' << tree[i].value << '\n';
in.close();
out.close();
return 0;
}
void dfs(int node, ll currentCode, int codeLen)
{
if(tree[node].leftSon)
{
dfs(tree[node].leftSon, currentCode<<1, codeLen+1);
dfs(tree[node].rightSon, (currentCode<<1)+1, codeLen+1);
return;
}
sum += tree[node].value * codeLen;
tree[node].value = currentCode;
tree[node].leftSon = codeLen;
}