Parcurgere matrice in spirala

[•miculprogramator]

Salut !  Ma poate ajuta cineva cu o parcurgere in spirala a unei matrici ? Eu am reusit sa fac numai pentru cele patratice si m-am chinuit ceva ...

Asta e tot ce am reusit sa fac:

Cod:

for(k=1;k<=(nrlin+1)/2;k++)
       {
       for(j=k;j<=nrlin-k+1;j++)
          cout<<a[k][j]<<" ";
       for(i=k+1;i<=nrlin-k+1;i++)
          cout<<a[i][nrlin-k+1]<<" ";
       for(i=nrlin-k;i>=k;i--)
          cout<<a[nrlin-k+1][i]<<" ";
       for(i=nrlin-k; i>k;i--)
          cout<<a[i][k]<<" ";
    }

Din pacate imi omnite intotdeauna ultima coloana...

[•chera_lary]

Salut!  Uite aici codul! Il mai optimizezi tu daca e ceva, ca eu l-am scris in graba! Succces! 

Cod:

#include <iostream>
#include <conio.h>

using namespace std;

int a[100][100], a2[100][100];
int n, m;

int main(){
	cout<<"n:";cin>>n;
	cout<<"m:";cin>>m;
	
	for(int i=1;i<=n;i++)
	  for(int j=1;j<=m;j++){
		cout<<"a["<<i<<"]["<<j<<"]:";
		cin>>a[i][j];
      }

	for(int i=1;i<=n;i++){
	  for(int j=1;j<=m;j++)
		cout<<a[i][j]<<" ";
      cout<<endl;
	}
    cout<<endl;

	for(int k=0;k<=(n*m)/2;k++){
	  for(int i=1+k;i<=m-k;i++) {int l=k+1; if(!a2[l][i]) cout<<a[l][i]<<" ", a2[l][i]=1;}
	  for(int j=2+k;j<=n-k;j++) {int l=m-k; if(!a2[j][l]) cout<<a[j][l]<<" ", a2[j][l]=1;}
	  for(int i=m-1-k;i>=1+k;i--) {int l=n-k; if(!a2[l][i]) cout<<a[l][i]<<" ", a2[l][i]=1;}
	  for(int j=n-1-k;j>=2+k;j--) {int l=k+1; if(!a2[j][l]) cout<<a[j][l]<<" ", a2[j][l]=1;}
	}
	
	getch();
	
	return 0;
}

[•miculprogramator]

Mersi Laurentiu. Am primit ajutor intre timp, dar e binevenita si interventia ta. 

[•balakraz94]

Naspa rau codul .