Diferente pentru problema/jupanul intre reviziile #25 si #26
Nu exista diferente intre titluri.
Diferente intre continut:
Numarul $6$ se descompune in $2$ termeni astfel:
* [1,6], cost=gcd([1]) + gcd([1,6])=1+1=2 * [6,1], cost=gcd([6]) + gcd([6,1])=6+1=7 * [2,3], cost=gcd([2]) + gcd([2,3])=2+1=3 * [3,2], cost=gcd([3]) + gcd([3,2])=3+1=4
* [1,6], cost=gcd(%{color:black}$[1$%$]$) + gcd([1,6])=1+1=2
* [6,1], cost=gcd(%{color:black}$[6$%$]$) + gcd([6,1])=6+1=7
* [2,3], cost=gcd(%{color:black}$[2$%$]$) + gcd([2,3])=2+1=3
* [3,2], cost=gcd(%{color:black}$[3$%$]$) + gcd([3,2])=3+1=4
Deci $f(6,2)=2+7+3+4=16$
