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Borderou de evaluare (job #986703)
Raport evaluator
Compilare:
user.cpp: In function ‘int main()’:
user.cpp:62:48: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 3 has type ‘int’ [-Wformat=]
if(nLin) {printf("%s%ld\n",Coloana(nCol),nLin); nsir++;}
^
user.cpp:65:44: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
if(Rez[0].poz==1) printf("%ld ",Rez[0].rez);
^
user.cpp:66:37: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
else {printf("%ld 0 ",Rez[0].poz-1); printf("%ld ",Rez[0].rez);}
^
user.cpp:66:64: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
else {printf("%ld 0 ",Rez[0].poz-1); printf("%ld ",Rez[0].rez);}
^
user.cpp:68:61: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
if(Rez[i].poz==Rez[i-1].poz+1) printf("%ld ", Rez[i].rez);
^
user.cpp:69:53: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
else {printf("%ld 0 ",Rez[i].poz-Rez[i-1].poz-1); printf("%ld ",Rez[i].rez);}
^
user.cpp:69:80: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
else {printf("%ld 0 ",Rez[i].poz-Rez[i-1].poz-1); printf("%ld ",Rez[i].rez);}
^
Test |
Timp executie |
Memorie folosita |
Mesaj |
Punctaj/test |
1 | 0ms | 236kb | Raspuns corect | 10 |
2 | 0ms | 240kb | Raspuns corect | 10 |
3 | 0ms | 236kb | Raspuns corect | 10 |
4 | 0ms | 240kb | Raspuns corect | 10 |
5 | 0ms | 236kb | Raspuns corect | 10 |
6 | 0ms | 236kb | Raspuns corect | 10 |
7 | 4ms | 236kb | Raspuns corect | 10 |
8 | 0ms | 236kb | Raspuns corect | 10 |
9 | 4ms | 240kb | Raspuns corect | 10 |
10 | 0ms | 236kb | Raspuns corect | 10 |
Punctaj total | 100 |