Compilare: user.cpp: In function ‘void lee(char, char)’: user.cpp:9:10: warning: array subscript has type ‘char’ [-Wchar-subscripts] viz[x][y]=1; ^ user.cpp:9:13: warning: array subscript has type ‘char’ [-Wchar-subscripts] viz[x][y]=1; ^ user.cpp:10:23: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x>1&&viz[x-1][y]==0&&v[x][y]!=2&&v[x][y+1]!=4) ^ user.cpp:10:32: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x>1&&viz[x-1][y]==0&&v[x][y]!=2&&v[x][y+1]!=4) ^ user.cpp:10:35: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x>1&&viz[x-1][y]==0&&v[x][y]!=2&&v[x][y+1]!=4) ^ user.cpp:10:44: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x>1&&viz[x-1][y]==0&&v[x][y]!=2&&v[x][y+1]!=4) ^ user.cpp:12:18: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y<m&&viz[x][y+1]==0&&v[x][y+1]!=3&&v[x+1][y+1]!=1) ^ user.cpp:12:32: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y<m&&viz[x][y+1]==0&&v[x][y+1]!=3&&v[x+1][y+1]!=1) ^ user.cpp:14:23: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x<n&&viz[x+1][y]==0&&v[x+1][y]!=2&&v[x+1][y+1]!=4) ^ user.cpp:14:37: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(x<n&&viz[x+1][y]==0&&v[x+1][y]!=2&&v[x+1][y+1]!=4) ^ user.cpp:16:18: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y>1&&viz[x][y-1]==0&&v[x][y]!=3&&v[x+1][y]!=1) ^ user.cpp:16:32: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y>1&&viz[x][y-1]==0&&v[x][y]!=3&&v[x+1][y]!=1) ^ user.cpp:16:35: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y>1&&viz[x][y-1]==0&&v[x][y]!=3&&v[x+1][y]!=1) ^ user.cpp:16:49: warning: array subscript has type ‘char’ [-Wchar-subscripts] if(y>1&&viz[x][y-1]==0&&v[x][y]!=3&&v[x+1][y]!=1) ^ user.cpp: In function ‘int main()’: user.cpp:25:25: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘char*’ [-Wformat=] scanf("%d%d\n",&n,&m); ^ user.cpp:25:25: warning: format ‘%d’ expects argument of type ‘int*’, but argument 3 has type ‘char*’ [-Wformat=] user.cpp:26:18: warning: format ‘%s’ expects argument of type ‘char*’, but argument 2 has type ‘char (*)[10002]’ [-Wformat=] scanf("%s",&t);