Pagini recente » Cod sursa (job #1813604) | Cod sursa (job #251002) | Cod sursa (job #80753) | Cod sursa (job #3265860) | Cod sursa (job #833785)
Cod sursa(job #833785)
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 50000;
const int MOD = 10000;
int dp[2][2 * MAXN];
int main()
{
freopen("diamant.in", "r", stdin);
freopen("diamant.out", "w", stdout);
int n, m, x;
scanf("%d %d %d", &n, &m, &x);
int sum = ((n * (n + 1)) / 2) * ((m * (m + 1)) / 2);
if (x > sum || x < -sum) {
printf("0\n");
return 0;
}
int l = 0;
dp[0][sum] = 1;
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j, l = 1 ^ l) {
int k = 1 ^ l;
for (int s = -sum; s <= sum; ++s) {
dp[k][s + sum] = dp[l][s + sum];
if (s + i * j <= sum) {
dp[k][s + sum] += dp[l][s + sum + i * j];
if (dp[k][s + sum] >= MOD)
dp[k][s + sum] -= MOD;
}
if (s - i * j >= -sum) {
dp[k][s + sum] += dp[l][s + sum - i * j];
if (dp[k][s + sum] >= MOD)
dp[k][s + sum] -= MOD;
}
}
}
printf("%d\n", max(dp[1][x + sum], dp[0][x + sum]));
return 0;
}