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Cod sursa(job #799328)
#include<fstream>
#define LL long long
#define M 9973
#define NMAX 1000009 // un numar are divizori pana la jumatatea lui => n = 10^12 =>d <= 10^6
using namespace std;
LL n, d[50], p[50];
int t, k,semn[NMAX], ciur[NMAX],lng = 0;
inline void eratosthenes()
{
for(int i = 2; i <= NMAX; i+=2) semn[i] = 1;
ciur[0] = 2;
lng = 1;
for(int i = 3; i <= NMAX; i += 2)
{
if(!semn[i])
{
ciur[lng] = i;
lng++;
for(int j = i; j <= NMAX; j += i)semn[j] = 1;
}
}
}
int main()
{
ifstream f("ssnd.in");
ofstream g("ssnd.out");
f>>t;
eratosthenes();
for(int r = 1; r <= t; ++r)
{
f>>n;
LL nr;
LL sum;
nr = 1;
sum = 1;
for(int i = 0; ciur[i] * ciur[i] < n; ++i)
{
if(!(n % ciur[i]))
{
nr = (nr + 2) % M;
sum = (sum + ciur[i] + n / ciur[i]) % M;
}
}
sum = (sum + n) % M;
nr = (nr + 1) % M;
g<<nr<<' '<<sum <<'\n';
}
g.close();
return 0;
}