#include <fstream>

using namespace std;
ifstream fin ("divk.in");
ofstream fout ("divk.out");


int v[50007],m[3][50007];
int main()
{
    int n,a,b,k,i,nr,j,rest=0;
    fin>>n>>k>>a>>b;
    for (i=1;i<=n;i++)
        fin>>v[i];
    nr=0;
    for(i=2;i<=n;i++)
        for (j=2;j<=i;j++)
        {
            if ( j==2 )
                rest=(v[i-1]+v[i])%k;
            else
                rest=(m[!(i%2)][j-1]+v[i])%k;
            if(!rest&&j>=a&&j<=b)
                nr++;
            m[i%2][j]=rest;
        }
    fout<<nr;
    return 0;
}