using namespace std;
#include<cstdio>
#define MAX 7200
#define MAX2 930
#define MOD 9901
#define MOD2 999999997
#define llu(a) (a*1LL)
bool ciur[MAX];
int prim[MAX2],k=1;
void ciur_er()
{
	int i,j;
	prim[k]=2;
	for(i=3;i<MAX-1;i+=2)
		if(!ciur[i])
		{
			prim[++k]=i;
			for(j=i+i+i;j<MAX-1;j+=i+i)
				ciur[j]=1;
		}
}
inline long long pow(long long N,long long P)
{
	long long sol=1;
	while(P)
	{
		if(P&1)
			sol=(sol*N)%MOD2;
		N=(N*N)%MOD2;
		P>>=1;
	}
	return sol;
}
int main()
{
	freopen("sumdiv.in","r",stdin);
	freopen("sumdiv.out","w",stdout);
	ciur_er();
	int S=1,P,i;
	long long A,B,m;
	scanf("%lld %lld",&A,&B); // A la puterea B
	for(i=1;(llu(prim[i]*prim[i])<=A)&&(i<=k);i++)
	{
		if(A%prim[i])
			continue;
		m=A;
		while(A%prim[i]==0)
			A=A/prim[i];
		P=((pow(m/A,B)*llu(prim[i])-1)/((llu(prim[i])-1)))%MOD;
		S=(S*P)%MOD;
	}
	if(A!=1)
		S=(llu(S)*(pow(A,B+1)-1)/(A-1))%MOD;
	printf("%d\n",S);
	return 0;
}