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Cod sursa(job #719269)
#include<fstream>
#include<cmath>
#include <cstdio>
#define dim 10000
#define FOR for(i=1;i<=n;i++)
using namespace std;
ifstream f("patrate2.in");
ofstream g("patrate2.out");
int a[dim];
int n,k=1;
int i;
int nr=0;
void solvation(int x)
{
int y=0;
for(int i=1;i<=k;++i)
{
int x=a[i]*x;
a[i]=(nr+y)%dim;
y=(nr+y)/dim;
}
while(y)
{
a[++k]=y%dim;
y=y/dim;
}
}
int main()
{
f>>n;
a[1]=1;
for(i=1;i<=n*n;++i)
solvation(2);
FOR
solvation(2);
g<<a[k];
for(i=k-1;i>=1;--i)
g<<a[i]<<" ";
return 0;
}