Borderou de evaluare (job #648015)
Utilizator | Data | 12 decembrie 2011 22:07:17 | |
---|---|---|---|
Problema | Secvdist | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp: In function ‘int main()’:
user.cpp:8: warning: format ‘%d’ expects type ‘int*’, but argument 2 has type ‘long int*’
user.cpp:9: warning: format ‘%d’ expects type ‘int*’, but argument 2 has type ‘long int*’
user.cpp:10: warning: format ‘%d’ expects type ‘int*’, but argument 2 has type ‘long int*’
user.cpp:11: error: expected ‘;’ before ‘max_secv’
user.cpp:21: warning: format ‘%d’ expects type ‘int*’, but argument 2 has type ‘long int*’
user.cpp:86: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘long int’
user.cpp:6: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result
user.cpp:7: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result
user.cpp:8: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
user.cpp:9: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
user.cpp:11: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
user.cpp:21: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
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