Borderou de evaluare (job #622375)
Utilizator | Data | 17 octombrie 2011 21:31:49 | |
---|---|---|---|
Problema | Edist | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp:38: error: expected ‘,’ or ‘...’ before ‘k’
user.cpp: In function ‘int levenstein(char*, char*, int, int)’:
user.cpp:54: error: ‘lens2’ was not declared in this scope
user.cpp: In function ‘int main()’:
user.cpp:90: warning: format ‘%d’ expects type ‘int*’, but argument 2 has type ‘short int*’
user.cpp:90: warning: format ‘%d’ expects type ‘int*’, but argument 3 has type ‘short int*’
user.cpp:90: warning: format ‘%d’ expects type ‘int*’, but argument 4 has type ‘short int*’
user.cpp:91: warning: format ‘%s’ expects type ‘char*’, but argument 2 has type ‘char**’
user.cpp:92: warning: format ‘%s’ expects type ‘char*’, but argument 2 has type ‘char**’
user.cpp:38: error: too many arguments to function ‘int levenstein(char*, char*, int, int)’
user.cpp:95: error: at this point in file
user.cpp:95: warning: format ‘%s’ expects type ‘char*’, but argument 2 has type ‘int’
user.cpp:86: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result
user.cpp:87: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result
user.cpp:90: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
user.cpp:91: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
user.cpp:92: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
- Daca tot nu e bine, contacteaza-ne pe forum !