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Cod sursa(job #545311)
// se transforma vectorul cu valori de max 2 miliarde in vector cu valori de max 5000.
#include<cstdio>
#include<vector>
#include<algorithm>
using namespace std;
const int N=5005;
vector <pair < int,int > > a(N);
int n,x[N],pozi[N],upoz[N];
void citire()
{
freopen("secv.in","r",stdin);
freopen("secv.out","w",stdout);
scanf("%d",&n);
for (int i=1;i<=n;++i)
{
scanf("%d",&a[i].first);
a[i].second=i;
}
sort(&a[1],&a[n+1]);
x[a[1].second]=1;
for (int i=2;i<=n;++i)
if (a[i].first==a[i-1].first)
x[a[i].second]=x[a[i-1].second];
else
x[a[i].second]=x[a[i-1].second]+1;
}
int aflumax(int a[])
{
int max=x[1];
for (int i=2;i<=n;++i)
if (x[i]>max)
max=x[i];
return max;
}
void rez()
{
for (int i=1;i<=n;++i)
if (x[i]==1)
{
upoz[1]=i;
pozi[1]=i;
}
else
{
upoz[x[i]]=i;
pozi[x[i]]=pozi[x[i]-1];
}
int xx=aflumax(x);
printf("%d\n",upoz[xx]-pozi[xx]+1);
}
int main()
{
citire();
rez();
return 0;
}