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Cod sursa(job #473261)
#include<fstream.h>
#include<math.h>
long n;
long long a[25000][2];
ifstream f("euclid2.in");
ofstream g("euclid2.out");
long long euclid(long long a,long long b)
{
if(a==b) return a;
else{
if(a>b) return euclid(a-b,b);
else return euclid(a,b-a);
}
}
int main()
{
long long i;
f>>n;
i=0;
for(i=0;i<n;i++)
{
f>>a[i][1]>>a[i][2];
g<<euclid(a[i][1],a[i][2]);
}
f.close();
g.close();
return 0;
}