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Cod sursa(job #473258)
#include<fstream.h>
#include<math.h>
long n;
long long a[25000][2];
ifstream f("euclid2.in");
ofstream g("euclid2.out");
int main()
{
long long i;
f>>n;
i=0;
for(i=0;i<n;i++)
{
f>>a[i][1]>>a[i][2];
while(a[i][1]!=a[i][2]){
if(a[i][1]>[i][2]) a[i][1]=a[i][1]/a[i][2];
else a[i][2]=a[i][2]/a[i][1];
}
g<<a[i][1];
}
f.close();
g.close();
return 0;
}