Cod sursa(job #3340752)

Utilizator Cezar2009Cezar Mihai Titihazan Cezar2009 Data 16 februarie 2026 12:04:22
Problema Patrate2 Scor 0
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 2.21 kb
//https://www.infoarena.ro/problema/100m

//#ifdef _MSC_VER
//	#define _CRT_SECURE_NO_WARNINGS
//#elif  __GNUC__
//	#pragma GCC optimize("Ofast,unroll-loops,inline")
//	#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
//#endif

//#define _USE_MATH_DEFINES

#include <iostream>
#include <fstream>
#include <utility>
#include <cstdint>
//#include <cstdio>
//#include <algorithm>
//#include <vector>
//#include <array>
//#include <list>
//#include <forward_list>
//#include <string>
//#include <cstring>
//#include <cmath>
//#include <bitset>
//#include <queue>
//#include <stack>
//#include <map>
//#include <set>
//#include <unordered_map>
//#include <unordered_set>
//#include <limits>
//#include <climits>
//#include <iomanip>
//#include <tuple>
//#include <numeric>
//#include <chrono>
//#include <memory>

using namespace std;

using int64 = int64_t;
using uint64 = uint64_t;
using int16 = int16_t;
using uint16 = uint16_t;
using pii = pair<int, int>;
using pll = pair<int64, int64>;

#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
#define pb push_back
#define for0(i,n) for(int i=0; i<(n); ++i)
#define for1(i,n) for(int i=1; i<=(n); ++i)
#define foreach(x,a) for(auto& x : a)
#define cforeach(x,a) for(const auto& x : a)
#define cendl cout << "\n"
#define fendl fout << "\n"
#define FASTIO ios::sync_with_stdio(false); cin.tie(nullptr);

ifstream fin("100m.in");
ofstream fout("100m.out");

//FILE* fin = fopen("", "r");
//FILE* fout = fopen("", "w");

const int MOD = 666013;
const int NRMAX = 5000;

int power_of_manyyy(int b, int e, int modulo)
{
	int rez = 1;

	while (e > 0)
	{
		if (e & 1)
			rez = (int64)rez * b % modulo;

		b = (int64)b * b % modulo;
		e >>= 1;
	}

	return rez;
}

int invMod(int x, int m)
{
	return power_of_manyyy(x, m - 2, m);
}


int dp[2][NRMAX + 1]

int main()
{
	//FASTIO;
	
	int n, fact = 1;

	fin >> n;

	dp[0] = 1;
	for (int i = 1; i < n; ++i)
	{
		for (int j = 1; j <= i; ++j)
		{
			dp[i & 1][j] = (j + 1) * dp[(i + 1) & 1][j] + dp[(i + 1) & 1][j - 1] % MOD;
		}
	}
	for1(i, n)
	{
		rez = (rez + dp[] *)
			fact = fact * i % MOD;
	}


	fout << rez;
	fendl;

	return 0;
}