Pagini recente » Borderou de evaluare (job #1959762) | Borderou de evaluare (job #627531) | Borderou de evaluare (job #1595405) | Borderou de evaluare (job #1805122) | Cod sursa (job #3338457)
#include <stdio.h>
#include <stdlib.h>
#define N 100000
char s[N+1];
int p;
int expresie();
int termen();
int factor();
int main()
{
FILE *in, *out;
in = fopen("evaluare.in", "r");
fgets(s, N + 1, in);
fclose(in);
out = fopen("evaluare.out", "w");
p = 0;
fprintf(out, "%d\n", expresie());
fclose(out);
return 0;
}
int expresie()
{
int sum = termen();
while (s[p] == '+' || s[p] == '-')
{
if (s[p] == '+')
{
p++;
sum += termen();
}
else
{
p++;
sum -= termen();
}
}
return sum;
}
int termen()
{
int prod = factor();
while (s[p] == '*' || s[p] == '/')
{
if (s[p] == '*')
{
p++;
prod *= factor();
}
else
{
p++;
prod /= factor();
}
}
return prod;
}
int factor()
{
int val = 0, semn = 1;
while (s[p] == '-')
{
p++;
semn = (-semn);
}
if (s[p] == '(')
{
p++;
val = expresie();
p++;/// pentru ')'
return semn * val;
}
while ('0' <= s[p] && s[p] <= '9')
{
val = val * 10 + (s[p] - '0');
p++;
}
return semn * val;
}