Cod sursa(job #3276792)

Utilizator Maftei_TudorMaftei Tudor Maftei_Tudor Data 14 februarie 2025 18:41:56
Problema Aria Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.05 kb
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define fi first
#define sc second
#define pb push_back

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef long double db;
typedef pair<int, int> pii;
template<typename type>
using ordered_set = tree<type, null_type, less<type>, rb_tree_tag, tree_order_statistics_node_update>;

const int N = 1e5 + 5, mod = 1e9 + 7, inf = 2e9;
const int dl[] = {-1, 0, 1, 0}, dc[] = {0, 1, 0, -1};
const int ddl[] = {-1, -1, -1, 0, 1, 1, 1, 0}, ddc[] = {-1, 0, 1, 1, 1, 0, -1, -1};

mt19937 gen(chrono::steady_clock::now().time_since_epoch().count());
int rng(int lo = 1, int hi = INT_MAX) {
    uniform_int_distribution<int> rnd(lo, hi);
    return rnd(gen);
}

struct mint {
    int val;
    mint(int32_t x = 0) {
        val = x % mod;
    }
    mint(long long x) {
        val = x % mod;
    }
    mint operator+(mint x) {
        return val + x.val;
    }
    mint operator-(mint x) {
        return val - x.val + mod;
    }
    mint operator*(mint x) {
        return 1LL * val * x.val;
    }
    void operator+=(mint x) {
        val = (*this + x).val;
    }
    void operator-=(mint x) {
        val = (*this - x).val;
    }
    void operator*=(mint x) {
        val = (*this * x).val;
    }
    friend auto operator>>(istream& in, mint &x) -> istream& {
        in >> x.val;
        x.val %= mod;
        return in;
    }
    friend auto operator<<(ostream& out, mint const &x) -> ostream& {
        out << x.val;
        return out;
    }
};

struct point {
    db x, y;
};

int n;
point v[N];

db crosspr(point a, point b) {
    return a.x * b.y - a.y * b.x;
}

int32_t main() {
    freopen("aria.in", "r", stdin);
    freopen("aria.out", "w", stdout);
    cin.tie(nullptr)->sync_with_stdio(0);

    cin >> n;
    for(int i=1; i<=n; i++)
        cin >> v[i].x >> v[i].y;
    
    db ans = 0;
    for(int i=1; i<=n; i++) {
        int j = i < n ? i + 1 : 1;
        ans += crosspr(v[i], v[j]);
    }
    ans /= 2;

    cout << fixed << setprecision(5) << ans;
    return 0;
}