Cod sursa(job #3040077)

Utilizator unomMirel Costel unom Data 29 martie 2023 12:10:29
Problema Evaluarea unei expresii Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.02 kb
/*#include <fstream>

using namespace std;

ifstream f("evaluare.in");
ofstream g("evaluare.out");
int i = 0;
char s[10000];

int constanta();
int factor();
int termen();
int expresie();

int constanta()
{
    int r = 0;
    while(s[i] > '0' && s[i] < '9')
    {
        r = r*10 + (s[i] - '0');
        i++;
    }
    return r;
}

int factor()
{
    int r;
    if(s[i] == '(')
    {
        i++;
        r = expresie();
        i++;
    }
    else
    {
        r = constanta();
    }
    return r;
}

int termen()
{
    int r = factor();
    while(s[i] == '*' || s[i] == '/')
    {
        if(s[i] == '*')
        {
            i++;
            r *= factor();
        }
        else
        {
            i++;
            r /= factor();
        }
    }
    return r;
}

int expresie()
{
    int r = termen();
    while(s[i] == '+' || s[i] == '-')
    {
        if(s[i] == '+')
        {
            i++;
            r += termen();
        }
        else
        {
            i++;
            r -= termen();
        }
    }

    return r;
}

int main()
{
    f>>s;
    i = 0;
    g<<expresie();
    return 0;
}*/

#include <iostream>
#include <fstream>
#include <cstring>
using namespace std;
ifstream fin ("evaluare.in");
ofstream fout ("evaluare.out");
char s[100002];
int i;
int expr();
int term();
int fact();
int main()
{
    fin >>s;
    i=0;
    fout<<expr();
    return 0;
}
int expr()
{
    int x=term();
    while (s[i]=='+' || s[i]=='-')
          {i++;
           if (s[i-1]=='+') x+=term();
           else x-=term();}
    return x;
}
int term()
{
    int x=fact();
    while (s[i]=='*' || s[i]=='/')
          {i++;
           if (s[i-1]=='*') x*=fact();
           else x/=fact();}
    return x;
}
int fact()
{
    int x=0;
    if (s[i]=='(') {i++;
                    x=expr();
                    i++;}
    else {while (s[i]>='0' && s[i]<='9')
                {x=x*10+s[i]-'0';
                 i++;}}
    return x;
}