#include <iostream>
#include <fstream>
using namespace std;
ifstream fin ("mins.in");
ofstream fout ("mins.out");
const int nmax=1000005;
int cnt[nmax],c,d;
int main()
{
    fin >>c>>d;
    c--;d--;
    long long nrp=0;
    for (int k=2;k<=min(c,d);k++)
        {int x=1-cnt[k];
         if (x==0) continue;
         nrp+=1LL*x*(c/k)*(d/k);
         for (int m=2*k;m<=min(c,d);m=m+k)
             {cnt[m]+=x;}}
    fout <<1LL*c*d-nrp;
    return 0;
}