Pagini recente » Cod sursa (job #515098) | Cod sursa (job #2012235) | Cod sursa (job #1899077) | Cod sursa (job #981336) | Cod sursa (job #2836479)
#include <fstream>
using namespace std;
ifstream in("rucsac.in");
ofstream out("rucsac.out");
const int N=5000;
const int G=10000;
int profit[G+1],g[N+1],p[N+1];
int main()
{
int n, k;
in>>n>>k;
for (int i=0;i<n;i++)
{
in>>g[i]>>p[i];
}
for (int j=1;j<=k;j++)
{
profit[j]=-1;
}
for (int i=0;i<n;i++)
{
for (int j=k-g[i];j>=0;j--)
{
if (profit[j]!=-1)
{
profit[j+g[i]]=max(profit[j]+p[i], profit[j+g[i]]);
}
}
}
int maxim=0;
for (int i=1;i<=k;i++)
{
if (profit[i]>maxim)
maxim=profit[i];
}
out<<maxim;
return 0;
}