Cod sursa(job #2761539)

Utilizator C_R_I_S_T_I_2_3Cristi Gavrila C_R_I_S_T_I_2_3 Data 2 iulie 2021 16:54:55
Problema Evaluarea unei expresii Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.27 kb
#include <bits/stdc++.h>
#define paranteza 1000000001
#define inmultire 1000000002
#define scadere 1000000003
#define impartire 1000000004
using namespace std;
ifstream fin("evaluare.in");
ofstream fout("evaluare.out");
char a[100005];
int st[100005];
int top, x;
int main()
{
    fin >> a;
    for(int i=0; a[i]!=0;)
    {
        if(a[i]=='(')
        {
            st[++top]=paranteza;
            i++;
        }
        if(a[i]=='+')
        {
            i++;
        }
        if(a[i]=='-')
        {
            st[++top]=scadere;
            i++;
        }
        if(a[i]=='*')
        {
            st[++top]=inmultire;
            i++;
        }
        if(a[i]=='/')
        {
            st[++top]=impartire;
            i++;
        }
        if(isdigit(a[i]))
        {
            x=0;
            while(isdigit(a[i]))
            {
                x=x*10+(a[i]-'0');
                i++;
            }
            if(st[top]==scadere)
            {
                x=-x;
                top--;
            }
            while(st[top]==inmultire && top>0)
            {
                top--;
                x=st[top]*x;
                top--;
            }
            while(st[top]==impartire && top>0)
            {
                top--;
                x=st[top]/x;
                top--;
            }
            st[++top]=x;
        }
        if(a[i]==')')
        {
            x=0;
            while(st[top]!=paranteza && top>0)
            {
                x+=st[top];
                top--;
            }
            top--;  // stergerea parantezei deschise din stiva
            // calcularea numerelor din spatele parantezei
            while(st[top]==inmultire && top>0)
            {
                top--;
                x=st[top]*x;
                top--;
            }
            while(st[top]==impartire && top>0)
            {
                top--;
                x=st[top]/x;
                top--;
            }
            if(st[top]==scadere)
            {
                x=-x;
                top--;
            }
            st[++top]=x;
            i++;
        }
    }
    x=0;
    for(int i=1; i<=top; i++)
    {
        x+=st[i];
    }
    fout << x;
    return 0;
}