Pagini recente » Cod sursa (job #1368693) | Cod sursa (job #692078) | Cod sursa (job #2437145) | Cod sursa (job #1779739) | Cod sursa (job #2677554)
//TLE cu cautare binara si apm
//poate merge Dijkstra csf
#include <cstdio>
#include <algorithm>
#include <ctype.h>
#include <vector>
#include <queue>
#define MMAX 500000
#define NMAX 250000
using namespace std;
class InParser {
private:
FILE *fin;
char *buff;
int sp;
char read_ch() {
++sp;
if (sp == 4096) {
sp = 0;
fread(buff, 1, 4096, fin);
}
return buff[sp];
}
public:
InParser(const char* nume) {
fin = fopen(nume, "r");
buff = new char[4096]();
sp = 4095;
}
InParser& operator >> (int &n) {
char c;
while (!isdigit(c = read_ch()) && c != '-');
int sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
InParser& operator >> (long long &n) {
char c;
n = 0;
while (!isdigit(c = read_ch()) && c != '-');
long long sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
};
const int inf = 2000000000;
int n, m, x, y, dist[NMAX+10];
bool viz[NMAX+10];
vector <pair <int, int> > nod[NMAX+10];
priority_queue <pair <int, int>, vector <pair <int, int> >, greater < pair <int, int> > > pq;
int main()
{
InParser f("pscnv.in");
freopen("pscnv.out", "w", stdout);
f >> n >> m >> x >> y;
for(int i=1; i<=m; i++)
{ int nod1, nod2, cost;
f >> nod1 >> nod2 >> cost;
nod[nod1].push_back({cost, nod2});
nod[nod2].push_back({cost, nod1});
}
pq.push({0, x});
for(int i=1; i<=n; i++) dist[i] = inf;
dist[x] = 0;
while(!pq.empty())
{ pair <int, int> a = pq.top();
pq.pop();
if(a.second == y)
{ printf("%d\n", a.first);
return 0;
}
if(viz[a.second]) continue;
viz[a.second] = 1;
for(int i=0; i<nod[a.second].size(); i++)
if(!viz[nod[a.second][i].second])
{ int d = max(a.first, nod[a.second][i].first);
if(d < dist[nod[a.second][i].second])
{ dist[nod[a.second][i].second] = d;
pq.push({d, nod[a.second][i].second});
}
}
}
return 0;
}