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Cod sursa(job #265872)
#include<fstream>
#include<iostream>
using namespace std;
long power(long n, long p)
{ int x;
if(p==0) return 1;
if(p%2==0)
{ x=power(n, p/2);
return x*x;
}
else
return n*power(n, p-1);
}
int main()
{
long n, p, s;
ifstream f("lgput.in");
f>>n>>p;
f.close();
s=power(n,p);
ofstream g("lgput.out");
g<<s%1999999973;
g.close();
return 0;
}