Pagini recente » Cod sursa (job #2078958) | Cod sursa (job #3231660) | Cod sursa (job #1084415) | Borderou de evaluare (job #762912) | Cod sursa (job #2614256)
#include <fstream>
#include <algorithm>
using namespace std;
ifstream f("rmq.in");
ofstream g("rmq.out");
int n, m, i, j, p, a[25][100005];
int main()
{
f >> n >> m;
for(i = 1; i <= n; i++)
f >> a[0][i];
for(i = 1; (1 << i) <= n; i++)
for(j = 1; j <= n; j++)
a[i][j] = min(a[i - 1][j], a[i - 1][j + (1 << (i - 1))]); /// a[i][j] = minimul pe intervalul [j, j + 2 ^ i]
while(m)
{
f >> i >> j;
p = 0;
while((1 << p) <= j + 1 - i)
p++;
p--; /// aflam p astef incat 2 ^ p < lungimea intervalului, p - maxim posibil
g << min(a[p][i], a[p][j + 1 - (1 << p)]) << '\n';
m--;
}
f.close();
g.close();
return 0;
}