Cod sursa(job #2568413)

Utilizator Serban_sebastianSerban Sebastian Mihai Serban_sebastian Data 3 martie 2020 22:42:38
Problema Iepuri Scor 0
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 2.01 kb
#include<bits/stdc++.h>
#define n 3
#define cnt 666013
using namespace std;
ifstream fin("iepuri.in");
ofstream fout("iepuri.out");
int zile, a[4][4], b[4][4], c[4][4], A, B, C, x, y, z, quiz;

void expo(int power)
{
    for(int i=1; i<=n; i++)
        for(int j=1; j<=n; j++)
            if(i == j)
                b[i][j] = 1;
            else
                b[i][j] = 0;
    for(int p=0; p<power; p++)
    {
        if(((1<<p) & power) > 0)
        {
            for(int i=1; i<=n; i++)
                for(int j=1; j<=n; j++)
                {
                    c[i][j] = 0;
                    for(int k=1; k<=n; k++)
                    {
                        c[i][j] += (b[i][k] * a[k][j]) % cnt;
                        c[i][j] %= cnt;
                    }
                }
            for(int i=1; i<=n; i++)
                for(int j=1; j<=n; j++)
                    b[i][j] = c[i][j];
        }
        for(int i=1; i<=n; i++)
            for(int j=1; j<=n; j++)
            {
                c[i][j] = 0;
                for(int k=1; k<=n; k++)
                {
                    c[i][j] += (a[i][k] * a[k][j]) % cnt;
                    c[i][j] %= cnt;
                }
            }
        for(int i=1; i<=n; i++)
            for(int j=1; j<=n; j++)
                a[i][j] = c[i][j] % cnt;
    }
}
int main()
{
    fin >> quiz;
    for(int p=1; p<=quiz; p++)
    {
        fin >> x >> y >> z >> A >> B >> C >> zile;
        if(zile == 1)
            fout << y << '\n';
        if(zile == 2)
            fout << z << '\n';
        if(zile > 2)
        {
            a[1][1] = 0;
            a[1][2] = 0;
            a[1][3] = C;
            a[2][1] = 1;
            a[2][2] = 0;
            a[2][3] = B;
            a[3][1] = 0;
            a[3][2] = 1;
            a[3][3] = A;
            expo(zile-2);
            fout << ((x * b[1][3]) % cnt + (y * b[2][3]) % cnt + (z * b[3][3]) %cnt) % cnt << '\n';
        }
    }
    fout.close();
    return 0;
}