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Cod sursa(job #256065)
#include<iostream.h>
#include<fstream.h>
#include<string.h>
char *p,x[2000020],n[2000020];
int v[1001];
long i;
int main()
{
ifstream f("strmatch.in");
ofstream g("strmatch.out");
f.get(x,900);
f.get();
f.get(n,900);
f.get();
p=n;
do
{
p=strstr(p,x);
v[++v[0]]=p-x-2000020;
if(v[0]>1000)break;
p++;
}
while(p)
if(v[0]>1000)v[0]=1000;
g<<v[0]<<'\n';
for(i=1;i<=v[0];i++)g<<v[i]<<" ";
return 0;
}