Borderou de evaluare (job #2552958)
Utilizator | Data | 21 februarie 2020 13:14:03 | |
---|---|---|---|
Problema | Barbar | Status | done |
Runda | Arhiva de probleme | Compilator | cpp-64 | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
main.cpp:3:30: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:3:35: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:3:46: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:3:51: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:3:59: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:3:64: error: 'dim' was not declared in this scope
int is, js, it , jt, n, m, a[dim][dim], dist[dim][dim], d[dim][dim];
^~~
main.cpp:4:20: error: scalar object 'di' requires one element in initializer
int di={-1, 0, 0, 1};
^
main.cpp:5:20: error: scalar object 'dj' requires one element in initializer
int dj={0, 1, -1, 0};
^
main.cpp: In function 'int verif(int, int)':
main.cpp:12:10: warning: self-comparison always evaluates to true [-Wtautological-compare]
if (i<=i && i<=n && 1<=j && j<=m && f[i][j]==0)
~^~~
main.cpp:12:41: error: 'f' was not declared in this scope
if (i<=i && i<=n && 1<=j && j<=m && f[i][j]==0)
^
main.cpp: At global scope:
main.cpp:16:9: error: 'dim' was not declared in this scope
coada c[dim*dim];
^~~
main.cpp:16:13: error: 'dim' was not declared in this scope
coada c[dim*dim];
^~~
main.cpp: In function 'int lee(int, int)':
main.cpp:21:13: error: 'f' was not declared in this scope
f[i][j]=0;
^
main.cpp:22:5: error: 'c' was not declared in this scope
c[1].lin=is;
^
main.cpp:24:12: error: 'p' was not declared in this scope
while (p<=u)
^
main.cpp:24:15: error: 'u' was not declared in this scope
while (p<=u)
Non zero exit status: 1
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
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