Borderou de evaluare (job #2500675)
Utilizator | Data | 28 noiembrie 2019 15:23:54 | |
---|---|---|---|
Problema | Asmax | Status | done |
Runda | Arhiva de probleme | Compilator | cpp-64 | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
main.cpp:7:8: warning: character constant too long for its type
filein='asmax.in';
^~~~~~~~~~
main.cpp:9:9: warning: character constant too long for its type
fileout='asmax.out';
^~~~~~~~~~~
main.cpp:7:1: error: 'filein' does not name a type
filein='asmax.in';
^~~~~~
main.cpp:9:1: error: 'fileout' does not name a type
fileout='asmax.out';
^~~~~~~
main.cpp:11:1: error: 'type' does not name a type
type longarray=array[1.MAXN] of longint;
^~~~
main.cpp:13:1: error: 'plongarray' does not name a type
plongarray=^longarray;
^~~~~~~~~~
main.cpp:15:1: error: 'plist' does not name a type
plist=^list;
^~~~~
main.cpp:17:1: error: 'list' does not name a type
list=record
^~~~
main.cpp:22:4: error: found ':' in nested-name-specifier, expected '::'
urm:
^
main.cpp:22:1: error: 'urm' does not name a type
urm:
^~~
main.cpp:25:1: error: 'end' does not name a type
end;
^~~
main.cpp:27:1: error: 'var' does not name a type
var edge:
^~~
main.cpp:30:1: error: 'v' does not name a type
v,max,tata:
^
main.cpp:33:2: error: found ':' in nested-name-specifier, expected '::'
n:
^
main.cpp:33:1: error: 'n' does not name a type
n:
^
main.cpp:36:1: error: 'procedure' does not name a type
procedure readinput;
^~~~~~~~~
main.cpp:38:1: error: 'var' does not name a type
var i,j,k:
Non zero exit status: 1
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