// Calculati ultima cifra a sumei 1 ^ 1 + 2 ^ 2 + ... + N ^ N petnru T valori ale lui N.

#include <fstream>
#include <cstring>

using namespace std;

ifstream fin ("cifra.in");
ofstream fout ("cifra.out");

int cifre[101] = { 0,
                   1,5,2,8,3,9,2,8,7,7,8,2,9,5,0,6,9,5,4,4,5,9,6,2,7,
                   3,6,2,1,1,2,6,3,9,4,0,3,9,8,8,9,3,0,6,1,7,0,6,5,5,
                   6,0,7,3,8,4,7,3,2,2,3,7,4,0,5,1,4,0,9,9,0,4,1,7,2,
                   8,1,7,6,6,7,1,8,4,9,5,8,4,3,3,4,8,5,1,6,2,5,1,0,0 };

int main() {
    int T, i, l, a, b, nr;
    char sir[225];

    fin >> T;
    for (i = 1; i <= T; i++) {
        fin.get();
        fin.get(sir, 225);
        l = strlen(sir);
        if (l >= 2) {
            a = sir[l - 2] - '0';
            b = sir[l - 1] - '0';
            nr = 10 * a + b;
        } else 
            nr = sir[0] - '0';
        fout << cifre[nr] << '\n';
    }

    return 0;
}