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#include<fstream>
#include<queue>
#define f first
#define s second
#define DIM 400*2+4
#define dim 400
using namespace std;
ifstream fin("furtuna.in");
ofstream fout("furtuna.out");
vector<int> l[DIM];
deque<int> co;
vector<pair<int,int> > v[dim];
int j,viz[DIM],d[DIM],n,c,t,m,i,a,b,start,fina,mini,nod,sol;
int k[DIM][DIM],cost[DIM][DIM],C[dim],T[dim],ta[DIM],curr[DIM][DIM];
priority_queue<pair<int,int>, vector<pair<int,int> >, greater<pair<int,int> > >q;
int bellma()
{
int nod;
for(int i=1;i<=n;i++) d[i]=1000000000,viz[i]=0;
d[start]=0;viz[start]=1;
co.clear();co.push_back(start);
while(!co.empty())
{
nod=co.front();
co.pop_front();
viz[nod]=0;
for(auto vecin:l[nod])
{
if(k[nod][vecin]>curr[nod][vecin]&&d[vecin]>d[nod]+cost[nod][vecin])
{
d[vecin]=d[nod]+cost[nod][vecin];
ta[vecin]=nod;
if(viz[vecin]==0)
{
co.push_back(vecin);
viz[vecin]=1;
}
}
}
}
if(d[fina]==1000000000)
return 0;
else
return 1;
}
void dai(int p,int poz)
{
int i,nod;
for(i=1;i<=n;i++) d[i]=1000000000,viz[i]=0;
d[p]=0;
q.push(make_pair(0,p));
while(!q.empty())
{
nod=q.top().s;q.pop();
if(viz[nod]==1) continue;
viz[nod]=1;
for(auto it:v[nod])
if(viz[it.f]==0&&d[it.f]>d[nod]+it.s)
{
d[it.f]=d[nod]+it.s;
q.push(make_pair(d[it.f],it.f));
}
}
for(i=1;i<=c;i++)
{
k[poz][1+t+i]=1;
l[poz].push_back(1+t+i);
l[1+t+i].push_back(poz);
cost[poz][1+t+i]=d[C[i]];
cost[1+t+i][poz]=-d[C[i]];
fout<<poz-1<<" "<<C[i]<<" "<<cost[poz][1+t+i]<<"\n";
}
}
int main()
{
fin>>n>>m>>t>>c;
for(i=1;i<=m;i++)
{
fin>>a>>b>>c;
v[a].push_back(make_pair(b,c));
v[b].push_back(make_pair(a,c));
}
for(i=1;i<=t;i++)
{
fin>>T[i];
l[1].push_back(i+1);
l[i+1].push_back(1);
k[1][i+1]=1;
}
for(i=1;i<=c;i++)
{
fin>>C[i]>>a;
l[i+t+1].push_back(c+t+2);
l[c+t+2].push_back(i+t+1);
k[i+t+1][c+t+2]=a;
}
for(i=1;i<=t;i++) dai(T[i],i+1);
start=1;fina=t+c+2;n=fina;
while(bellma())
{
mini=1000000000;nod=fina;
while(ta[nod])
{
mini=min(mini,k[ta[nod]][nod]-curr[ta[nod]][nod]);
nod=ta[nod];
}
nod=fina;
while(ta[nod])
{
curr[ta[nod]][nod]+=mini;
curr[nod][ta[nod]]-=mini;
nod=ta[nod];
}
}
for(i=2;i<=t+1;i++) for(j=t+2;j<=t+c+1;j++)
{
sol=max(sol,curr[i][j]*cost[i][j]);
fout<<T[i-1]<<" "<<C[j-t-1]<<" "<<curr[i][j]<<"\n";
}
fout<<sol;
return 0;
}