#include <fstream>

using namespace std;

ifstream f ("lacate.in");
ofstream g ("lacate.out");

int n;
int a[300];

int main()
{
    f >> n;

    g << n * (n - 1) / 2 << " " <<  n - 1 << '\n';

    int in = 1;
    for (int i = 1; i <= n; ++i)
    {
        for (int j = 1; j <= n - 1; ++j)
        {
            g << in << " ";
            in++;
            if (in > n * (n - 1) / 2) in = 1;
        }
        g << '\n';
    }

    return 0;
}