Cod sursa(job #2384049)
Utilizator | Data | 20 martie 2019 10:02:15 | |
---|---|---|---|
Problema | Diamant | Scor | 100 |
Compilator | cpp-64 | Status | done |
Runda | Teme Pregatire ACM Unibuc 2013 Semestrul 2 | Marime | 0.66 kb |
#include <bits/stdc++.h>
#define MOD 10000
using namespace std;
ifstream f("diamant.in");
ofstream g("diamant.out");
int a[2][160010],n,m,x,y=1;
long long val;
int main()
{
f>>n>>m>>x;
a[0][0]=a[0][1]=val=1;
for(int i=1; i<=n; i++)
{
for(int j=1; j<=m; j++)
{
if(i==1 && j==1) continue;
val+=i*j;
for(int k=0; k<=val; k++)
{
a[y%2][k]=((a[(y+1)%2][k+i*j]+a[(y+1)%2][abs(k-i*j)])%MOD+a[(y+1)%2][k])%MOD;
}
y++;
}
}
x=abs(x);
if(x>160000)g<<0<<'\n';
else g<<a[(y+1)%2][x]%MOD<<'\n';
return 0;
}