Cod sursa(job #2381145)

Utilizator dadu2544Petrisor Alexandru dadu2544 Data 16 martie 2019 09:24:32
Problema Rj Scor 100
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 2.13 kb
#include <fstream>
#include <queue>
using namespace std;

ifstream in("rj.in");
ofstream out("rj.out");

int dx[]= {-1,-1,0,1,1,1,0,-1};
int dy[]= {0,1,1,1,0,-1,-1,-1};

char a[101][101];
int rl[101][101],jl[101][101];
int n,m,ans=99999,l,c;

struct pereche
{
    int first;
    int second;
} rStart, jStart;

bool check(int i,int j)
{
    return (i>=0 && i<n && j>=0 && j<m);
}
void lee(int t[101][101], pereche start)
{
    queue < pereche > q;
    pereche cur;
    int nx,ny;
    q.push(start);
    t[start.first][start.second]=1;
    while(!q.empty())
    {
        cur=q.front();
        q.pop();
        for(int i=0; i<8; ++i)
        {
            nx=cur.first+dx[i];
            ny=cur.second+dy[i];
            if(check(nx,ny))
            {
                if(a[nx][ny]!='X' && t[nx][ny]==-1)
                {
                    t[nx][ny]=t[cur.first][cur.second]+1;
                    pereche lol;
                    lol.first=nx;
                    lol.second=ny;
                    q.push(lol);
                }
            }
        }
    }
}
int main()
{
    in>>n>>m;
    in.get();
    char s[101];
    for(int i=0; i<n; ++i)
    {
        in.getline(s,sizeof(s));
        for(int j=0; j<m; ++j)
        {
            a[i][j]=s[j];
            if(a[i][j]=='R')
            {
                pereche lol;
                lol.first = i;
                lol.second = j;
                rStart=lol;
            }
            else if(a[i][j]=='J')
            {
                pereche lol;
                lol.first = i;
                lol.second = j;
                jStart=lol;
            }
            rl[i][j]=jl[i][j]=-1;
        }

    }
    lee(rl,rStart);
    lee(jl,jStart);
    for(int i=0; i<n; ++i)
    {
        for(int j=0; j<m; ++j)
        {
            if(rl[i][j]==jl[i][j] && rl[i][j]!=-1)
            {
                if(rl[i][j]<ans)
                {
                    ans=rl[i][j];
                    l=i;
                    c=j;
                }
            }
        }
    }
    out<<ans<<" "<<l+1<<" "<<c+1;
    return 0;
}