Cod sursa(job #2368185)

Utilizator SirVSbiVidam Szablocs SirVSbi Data 5 martie 2019 14:28:09
Problema Distante Scor 0
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 1.93 kb
#include <iostream>
#include <vector>
#include <set>
#include <fstream>
#define MAX 100000
#define INF 99999999

using namespace std;

int main(){

    ifstream be("distante.in");
    ofstream ki("distante.out");

    int t;
    be >> t;

    while(t){

        int n, m, s;
        be >> n >> m >> s;

        vector<pair<int, int>> graph[MAX];
        long long dist[MAX];

        int dist1[n];
        for(int i = 0; i < n; i++){
            be >> dist1[i];
        }

        int from, to, cost;

        for(int i = 0; i < m; i++){
            be >> from >> to >> cost;
            graph[from].push_back(make_pair(to, cost));
            dist[i] = INF;
        }
        dist[1] = 0;
        set<pair<int, int>> heap;
        heap.insert(make_pair(0, s));
        while(!heap.empty()){

           int node = heap.begin() -> second;
            heap.erase(heap.begin());

            for(vector<pair<int, int>>::iterator it = graph[node].begin(); it != graph[node].end(); it++){
                to = it -> first;
                cost = it-> second;
                if(dist[to] > dist[node] + cost){
                    if(dist[to] != INF){
                        heap.erase(heap.find(make_pair(dist[to], to)));
                    }
                    dist[to] = dist[node] + cost;
                    heap.insert(make_pair(dist[to], to));
                }
            }

        }



        bool ok = true;
       for(int i = 2; i <= n; i++){
                if(dist[i] == INF){
                    dist[i] = 0;
                }
                if(dist1[i - 1] != dist[i])
                    ok = false;
        }

    /*    for(int i = 1; i <= n; i++){
            cout << dist1[i - 1] << " ";
        }
        cout << endl;

         for(int i = 1; i <= n; i++){
            cout << dist[i] << " ";
        }

        */
        if(ok){
            ki << "DA" << endl;
        }
        else{
            ki << "NU" << endl;
        }




        t--;
    }


}