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Cod sursa(job #232834)
#include <fstream.h>
int a[2000000], i, j, n, nr = 0;
int main()
{
ifstream fin("ciur.in");
fin >> n;
fin.close();
ofstream fout("ciur.out");
for ( i = 0; i < n; i++)
a[i] = 1;
for ( i = 2; i * i <= n; i++)
if ( a[i] )
{
j = 2;
while ( i*j < n )
{
a[i*j] = 0;
j++;
}
}
for ( i = 2; i <= n; i++)
if ( a[i] )
nr++;
fout << nr;
fout.close();
return 0;
}