Pagini recente » Cod sursa (job #1025469) | Cod sursa (job #1912437) | Cod sursa (job #338450) | Cod sursa (job #2251314) | Cod sursa (job #2308289)
#include <fstream>
using namespace std;
ifstream f("kruskal.in"); ///transport
ofstream g("kruskal.out");
int n,k,v[16000],i,maxi;
int nr_transp(int c) {
int nt=0, i=1, cc=c;
for (i=1; i<=n; )
if (v[i]<=cc) cc-=v[i], i++;
else nt++, cc=c;
return nt+1;
}
int cb(int k) { ///capacitatea minima m pt a face maxim k transporturi
int s=maxi, d=1000000000, m, pos, nt;
while(s<=d) {
m = s +(d-s)/2;
nt=nr_transp(m); /// nr transp la capacitatea m
if (nt==k) pos=m, d = m-1;
else if(nt>k) s=m+1;
else d=m-1;
}
return pos;
}
int main()
{
f>>n>>k;
for (i=1; i<=n; i++) {
f>>v[i];
if (v[i]>maxi) maxi=v[i];
}
//g<<nr_transp(6);
g<<cb(k);
return 0;
}