Pagini recente » Cod sursa (job #2555071) | Cod sursa (job #1057588) | Cod sursa (job #1829066) | Cod sursa (job #1187368) | Cod sursa (job #2284251)
#include <iostream>
#include <fstream>
using namespace std;
ifstream f("dijkstra.in");
ofstream g("dijkstra.out");
int main()
{
int n, m, x, y, cost;
f>>n>>m;
long **G;
G=new long *[n+1];
for(int i=0;i<=n;i++)
{
G[i]=new long [n+1];
for(int j=1;j<=n;j++)
G[i][j]=0;
}
for(int i=1;i<=m;i++)
{
f>>x>>y>>cost;
G[x][y]=cost;
}
long sol[n+1];
for(int i=1;i<=n;i++)
sol[i]=99999999;
sol[1]=0;
long coada[m+1], p, u;
p=u=1;
coada[p]=1;
while(p<=u)
{
for(int j=1;j<=n;j++)
{
if(G[coada[p]][j]!=0) //daca exista muchie
{
if(G[coada[p]][j]+sol[coada[p]]<sol[j])
{
sol[j]=G[coada[p]][j]+sol[coada[p]];
coada[++u]=j;
}
}
}
p++;
}
for(int i=2;i<=n;i++)
g<<sol[i]<<' ';
for(int i=0;i<=n;i++)
delete[] G[i];
delete[] G;
f.close();
g.close();
return 0;
}