Pagini recente » Cod sursa (job #3221183) | Cod sursa (job #3164539) | Cod sursa (job #1806273) | Cod sursa (job #1370442) | Cod sursa (job #2228888)
#include <stdio.h>
int p[(2000000 >> 6) + 1];
int sieve(register int n)
{
register int i, j, nr = 2;
for(i = 1; ((i * ++i) << 1) < n - 3; ++i)
{
if((p[i >> 5] & (1 << (i & 31))) == 0)
{
for(j = ((i * i) << 1) + (i << 1); (j << 1) < n; j += (i << 1) + 1)
{
p[j >> 5] |= (1 << (j & 31));
}
}
++i;
if((p[i >> 5] & (1 << (i & 31))) == 0)
{
for(j = ((i * i) << 1) + (i << 1); (j << 1) < n; j += (i << 1) + 1)
{
p[j >> 5] |= (1 << (j & 31));
}
}
}
for(i = 2; (i << 1) < n - 2; i += 3)
{
nr += ((p[ i >> 5] & (1 << ( i & 31))) == 0) +
((p[(i + 1) >> 5] & (1 << ((i + 1) & 31))) == 0);
}
return nr;
}
int main()
{
freopen("ciur.in", "r", stdin);
freopen("ciur.out", "w", stdout);
int N; scanf("%d", &N);
printf("%d ", sieve(N));
return 0;
}