#include <stdio.h>

int p[(100000000 >> 6) + 1];

int main()
{
    freopen("ciur.in", "r", stdin);
    freopen("ciur.out", "w", stdout);

    int n; scanf("%d", &n);

    register int i, j, k, nr = 1 + (n > 2);

    for(i = 2; ((i * i) << 1) + (i << 1) <= n - 2; i += 3)
    {
        if((p[i >> 5] & (1 << (i & 31))) == 0)
        {
            for(j = ((i * i) << 1) + (i << 1); (j << 1) < n; j += (i << 1) + 1)
            {
                p[j >> 5] |= (1 << (j & 31));
            }
        }

        k = i + 1;

        if((p[k >> 5] & (1 << (k & 31))) == 0)
        {
            for(j = ((k * k) << 1) + (k << 1); (j << 1) < n; j += (k << 1) + 1)
            {
                p[j >> 5] |= (1 << (j & 31));
            }
        }
    }

    for(i = 2; (i << 1) < n - 2; i += 3)
    {
        nr += ((p[ i      >> 5] & (1 << ( i      & 31))) == 0) +
              ((p[(i + 1) >> 5] & (1 << ((i + 1) & 31))) == 0);
    }

    printf("%d ", nr);

    return 0;
}