Borderou de evaluare (job #2187069)
Utilizator | Data | 26 martie 2018 10:31:34 | |
---|---|---|---|
Problema | Next | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp: In function ‘void hn_constr(int, int*)’:
user.cpp:11:24: warning: ‘sizeof’ on array function parameter ‘x’ will return size of ‘int*’ [-Wsizeof-array-argument]
memset(x,0,sizeof(x));
^
user.cpp:10:34: note: declared here
void hn_constr(int n,int x[NMAX+5]) {
^
user.cpp:11:22: warning: argument to ‘sizeof’ in ‘void* memset(void*, int, size_t)’ call is the same expression as the destination; did you mean to dereference it? [-Wsizeof-pointer-memaccess]
memset(x,0,sizeof(x));
^
user.cpp: In function ‘void hn_prod(int*, int*, int*)’:
user.cpp:24:24: warning: ‘sizeof’ on array function parameter ‘c’ will return size of ‘int*’ [-Wsizeof-array-argument]
memset(c,0,sizeof(c));
^
user.cpp:22:44: note: declared here
void hn_prod(int a[],int b[],int c[2*NMAX+5]) {
^
user.cpp:24:22: warning: argument to ‘sizeof’ in ‘void* memset(void*, int, size_t)’ call is the same expression as the destination; did you mean to dereference it? [-Wsizeof-pointer-memaccess]
memset(c,0,sizeof(c));
^
user.cpp: In function ‘void hn_divide(int*, long long int, int*)’:
user.cpp:43:23: error: ‘sizef’ was not declared in this scope
memset(c,0,sizef(c));
^
user.cpp: In function ‘int main()’:
user.cpp:72:9: error: ‘v’ was not declared in this scope
v[i]=ch;
^
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