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Borderou de evaluare (job #2168778)
Raport evaluator
Compilare:
user.cpp: In function ‘int main()’:
user.cpp:35:36: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result [-Wunused-result]
freopen("kinetic.in", "r", stdin);
^
user.cpp:36:38: warning: ignoring return value of ‘FILE* freopen(const char*, const char*, FILE*)’, declared with attribute warn_unused_result [-Wunused-result]
freopen("kinetic.out", "w", stdout);
^
user.cpp:37:24: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d", &n, &m);
^
user.cpp:39:36: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d", &v[i].x, &v[i].y);
^
user.cpp:48:32: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
scanf("%d%d%d", &a, &b, &t);
^
user.cpp:26:42: warning: array subscript is below array bounds [-Warray-bounds]
if(i + step < n && 1LL * v[a[i + step].poz].x + 1LL * v[a[i + step].poz].y * t <= val) {
^
user.cpp:26:42: warning: array subscript is below array bounds [-Warray-bounds]
if(i + step < n && 1LL * v[a[i + step].poz].x + 1LL * v[a[i + step].poz].y * t <= val) {
^
Test |
Timp executie |
Memorie folosita |
Mesaj |
Punctaj/test |
Punctaj/grupa |
1 | 0ms | 1304kb | OK | 10 | 10 |
2 | 0ms | 1388kb | OK | 10 | 10 |
3 | 0ms | 1324kb | OK | 10 | 10 |
4 | Depăşit | 1272kb | Time limit exceeded. | 0 | 0 |
5 | 460ms | 1308kb | OK | 10 | 0 |
6 | Depăşit | 1136kb | Time limit exceeded. | 0 |
7 | Depăşit | 1112kb | Time limit exceeded. | 0 |
8 | Depăşit | 1144kb | Time limit exceeded. | 0 |
9 | Depăşit | 1188kb | Time limit exceeded. | 0 |
10 | Depăşit | 1120kb | Time limit exceeded. | 0 |
Punctaj total | 30 |