using namespace std;

#include <cstdio>
#include <algorithm>
#include <cmath>

#define IN "atac.in"
#define OUT "atac.out"

#define min(x,y) x < y ? x : y
#define FOR(i,a,b) for(int i=a;i<=b;++i)
#define N_MAX 1<<15
#define M_MAX 1<<15

short int MA[N_MAX][1<<9];
int hg[N_MAX];
int CS[N_MAX],sol[M_MAX],tata[N_MAX];
short int stv[N_MAX],poz[N_MAX],lg[M_MAX],rmq[18][M_MAX];
short int TA[18][N_MAX],drum[18][N_MAX];
int q,rez,s,f,sef;
int maxhg,Z,X,Y,A,B,C,D,P,N,M;
bool bo[N_MAX];

void scan()
{
	int x,y;
	freopen(IN, "r",stdin);
	freopen(OUT, "w",stdout);
	scanf("%d%d%d\n", &N,&M,&P);
	
	FOR(i,1,N-1)
	{
		scanf("%d%d\n", &x,&y);
		tata[i+1] = x; 
		MA[ x ][ ++MA[x][0] ] = i+1;
		bo[i+1] = 1;
		CS[i+1] = y;
	}
	scanf("%d%d%d%d%d%d",&X,&Y,&A,&B,&C,&D);
	sef=1;
	FOR(i,1,N)
		if(!bo[i])
		{
			sef=i;
			break;
		}	
}

void euler(int nod,int niv)
{
	poz[nod] = stv[0] + 1;  
    hg[nod] = niv;  
	if(hg[nod] > maxhg)
		maxhg = hg[nod];
    stv[ ++stv[0] ] = nod;  
    FOR(i,1,MA[nod][0])  
    {  
        euler(MA[nod][i],niv+1);  
        stv[ ++stv[0] ] = nod;  
    } 
}

void process()
{
   --lg[0];
	FOR(i,1,stv[0])
		lg[i] = lg[i/2] + 1;
	
	FOR(i,1,stv[0])
		rmq[0][i] = stv[i];
		
	for(int i=1; (1<<i) <= stv[0];++i)
		for(int j=1;j+(1<<i)-1 <= stv[0];++j)
		{
			if(hg[ rmq[i-1][j] ] < hg[ rmq[i-1][ j+(1<<i) - (1<<(i-1))] ])
				rmq[i][j] = rmq[i-1][j];
			else
				rmq[i][j] = rmq[i-1][j+(1<<i) - (1<<(i-1))];
		}
	
	FOR(i,1,N)
		TA[0][i] = tata[i];
		
	for(int i=1; (1<<i) <= maxhg;++i)
		for(int j=1; j <= N  ;++j)
			TA[i][j] = TA[i-1][ TA[i-1][j] ];
			
	FOR(i,1,N)
		drum[0][i] = CS[i];
	
	for(int i=1; (1<<i) <= maxhg;++i)
		for(int j=1; j <= N  ;++j)
			drum[i][j] = min(drum[i-1][j],drum[i-1][ TA[i-1][j] ]);
}
 
inline int query(int nod1,int nod2)
{
	int x = poz[nod1],y = poz[nod2];
	if(x > y)
		swap(x,y);
	int dif = y-x+1;
	int log = lg[dif];
	if(hg[ rmq[log][x] ] < hg[ rmq[log][ y-(1<<log) + 1 ] ])
		return rmq[log][x];
	else
		return rmq[log][ y-(1<<log) + 1 ];
}

int querry_m(int x,int y)
{
	if(hg[y] == hg[x])
		return 1<<20;
	int log = lg[ hg[x]-hg[y] ];
	return min(drum[log][x],querry_m(TA[log][x],y) );
}

void solve()
{
	int nod;
	FOR(i,1,M)
	{
		rez =  0;
		rez =  1<<30;
		if(X == Y)
			rez=0;
		q = query(X,Y);
		
		nod=X;
		rez = min(rez,querry_m(X,q) );
		nod=Y;
		rez = min(rez,querry_m(Y,q) ); 	
				
		if(i > M-P)
			sol[ ++sol[0] ] = rez;
		//printf("intre %d si %d avem LCA : %d si alegem o strada %d\n",X,Y,q,rez);
		Z = rez;
		
		X = (X*A + Y*B) % (N-1) + 1;
		Y = (Y*C + Z*D) % (N-1) + 1;
	
	}
	
	FOR(i,1,sol[0])
		printf("%d\n", sol[i]);
}

int main()
{
	scan();
	euler(sef,1);
	++N;
	process();
	solve();
	return 0;
}